C语言中输入单个字符会屏蔽回车符如何解决

  介绍

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1,在scanf()中使用& # 39;\ n # 39;屏蔽回车符号。

scanf (“% d \ n",, n);//使用& # 39;\ n # 39;过滤回车

scanf (“% c",, c);

2,在scanf()格式串最前面添加空格,屏蔽回车字符

scanf (“% d",, n);

scanf (“% c",, c);//% c前面加空格,过滤回车

3,在接收字符前,使用获取字符()来读取一次回车符号

scanf (“% d",, n);   获取字符();//专门用来读取上次输入的回车符号   scanf (“% c",, c);

4,在接收字符前,使用。fflush()清空输入流中缓冲区中的内容

scanf (“% d",, n)   。fflush (stdin);//清空输入流缓冲区的字符,注意必须引入# include & lt; stdlib.h>头文件   scanf (“% c",, c);

好了,以后再也不用为这个问题烦恼了.....

<强> c语言中使用scanf()对字符(串)进行输入的问题

<强> 1。输入字符串

# include   int main () {   int;   char s1 [100];   char s2 [100];   scanf (“% d",,);   scanf (“% s", s1);   scanf (“% s", s2);   printf (“=% d \ n", a);   printf (“s1=% s \ n", s1);   printf (“s2=% s \ n", s2);   返回0;   }

输入

2019   你好   世界

输出

 # include
  int main () {
  int;
  char s1;
  char s2;
  scanf (“% d",,);
  scanf (“% c",, s1);
  scanf (“% c",, s2);
  printf (“=% d \ n", a);
  printf (“s1=% c \ n", s1);
  printf (“s2=% c \ n", s2);
  返回0;
  }

输入

2019   一个   

以前输出

 # include
  int main () {
  int;
  char s1;
  char s2;
  scanf (“% d",,);
  获取字符();//吸收“\ n"
  scanf (“% c",, s1);
  获取字符();//吸收“\ n"
  scanf (“% c",, s2);
  printf (“=% d \ n", a);
  printf (“s1=% c \ n", s1);
  printf (“s2=% c \ n", s2);
  返回0;
  }

在格式串中过滤掉回车

# include   int main () {   int;   char s1;   char s2;   scanf (“% d \ n", a);//过滤掉回车   scanf (“% c \ n", s1);   scanf (“% c",, s2);   printf (“=% d \ n", a);   printf (“s1=% c \ n", s1);   printf (“s2=% c \ n", s2);   返回0;   }

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C语言中输入单个字符会屏蔽回车符如何解决