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二。浮点数的加减乘除
警报(“1024.2,*,1.2,=,”,+,(1024.2,*,0.2);
三。解决方案
//,解决两个浮点数相乘丢失精度问题//,,,第一个参数//,,,第二个参数, function 和(a, b) { ,,,var weight =, 0; ,,,var aStr =, a.toString (); ,,,var bStr =, b.toString (); ,,,var regex =,/^ \ d + $/; ,,,, ,,,如果(! regex.test (aStr)) { ,,,,,,,weight +=, aStr.split (“。”) [1] . length;, ,,,,,,,aStr =, aStr.replace (“。”, " "); ,,,} ,,,如果(! regex.test(型)){ ,,,,,,,weight +=, bStr.split (“。”) [1] . length; ,,,,,,,bStr =, bStr.replace (“。”, " "); ,,,} ,,,return 数量(aStr), *,数量(型),/,Math.pow(10,重量); }
四。知识点
& lt; script type=" text/javascript祝辞 document . write (Math.floor (0.60), +,“& lt; br /祝辞”) document . write (Math.floor (0.40), +,“& lt; br /祝辞”) document . write (Math.floor (5), +,“& lt; br /祝辞”) document . write (Math.floor (5.1), +,“& lt; br /祝辞”) document . write (Math.floor (-5.1), +,“& lt; br /祝辞”) document . write (Math.floor (-5.9)) & lt;/script>
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五。学习博文